tag:blogger.com,1999:blog-3251724669642239513.post598385885850037959..comments2009-01-05T14:49:08.647-08:00Comments on Chess activity in W.N.Y.: Chess QuizDouglas Dubosehttp://www.blogger.com/profile/04189824812374133623noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-3251724669642239513.post-24155892604944259292008-12-07T19:09:00.000-08:002008-12-07T19:09:00.000-08:00And I guess in V. 1.Qc3 black can play 1. ... Bd7,...And I guess in V. 1.Qc3 black can play 1. ... Bd7, but 2.Rxd7 would win th B. (again unless there is something I do not see.<BR/>mprocykhttps://www.blogger.com/profile/05887228689863195621noreply@blogger.comtag:blogger.com,1999:blog-3251724669642239513.post-65498753201828045592008-12-06T21:52:00.000-08:002008-12-06T21:52:00.000-08:00This comment has been removed by the author.procykhttps://www.blogger.com/profile/05887228689863195621noreply@blogger.comtag:blogger.com,1999:blog-3251724669642239513.post-82989673729954977432008-12-05T18:17:00.000-08:002008-12-05T18:17:00.000-08:00I considered 3 options: Bd3, Bc4, Qc3I. 1.Bd3 Nxe3...I considered 3 options: Bd3, Bc4, Qc3<BR/>I. 1.Bd3 Nxe3? 2.Bxh7+ Kg7 Bxf6+ <BR/>II. 1.Bd3 f5? 2.Qc3 f6 3.Bd4 and Q is lost in both variations but I could not find an answer to<BR/>III. 2.Bd3 e5!. So I switched to:<BR/>IV. 1.Bc4 Nxe3 2.Bxa2 Nc2+ 3.Kd2 and N is lost for 2 pawns.<BR/>It seems intended solution would be:<BR/>V. 1.Qc3 (intending 2.Bc4) Nxe3 2. Qxf6 e5 3.Bxe5 Nc2+ 4.Kf2 Ne3 5.Kg1 and no more checks. or 3. ... Ng2+ 4.Bxg2 Qxg2 5.Qh8 mate.procykhttps://www.blogger.com/profile/05887228689863195621noreply@blogger.com